$\"\"$ $\"\"$

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The given line is $\"\"$ .

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above line is slope - intercept form $\"\"$ .

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So, given line has a slope of( $\"\"$ ) = 0.

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So, a line perpendicular to it has a slope of $\"\"$ .

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Because you know the slope and a point on the line,

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Use point - slope form $\"\"$ to write an equation of the line.

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Let $\"\"$ = $\"\"$ and slope( $\"\"$ ) = $\"\"$ .

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$\"\"$ (Substitute 2 for $\"\"$ , $\"\"$ 6 for $\"\"$ and $\"\"$ = $\"\"$ ) $\"\"$

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Rewrite in slope - intercept form $\"\"$ .

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$\"\"$ (Product of two sames signs is positive)

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$\"\"$ (Multiply each side by 0) \ \

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$\"\"$ (Cancel common terms) \ \

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$\"\"$ (Multiply: $\"\"$ )

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$\"\"$ (Apply distributive property: $\"\"$ )

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$\"\"$ (Multiply: $\"\"$ ) $\"\"$

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$\"\"$ (Subtract 6 from to each side)

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$\"\"$ (Apply additive inverse property: $\"\"$ )

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$\"\"$ (Apply additive identity property: $\"\"$ )

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$\"\"$ (Subtract: $\"\"$ ) $\"\"$

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Substitute $\"\"$ = $\"\"$ in equation $\"\"$ .

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$\"\"$

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The equation satisfies the condition.

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So,The equation of the line is $\"\"$ . $\"\"$

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The equation of the line is $\"\"$ .