Elimination method :
\The system of equations are
\
→ ( 1 )
→ ( 2 )
→ ( 3 )
Change the equations from fraction form to linear equation.
\The L.C.M of 3,4, and 8 in eq (1) is 24, so multiply eq (1) by 24.
\
→ ( 4 )
The L.C.M of 5,3, and 4 in eq (2) is 60, so multiply eq (2) by 60.
\
→ ( 5 )
The L.C.M of 5,3, and 8 in eq (3) is 120, so multiply eq (3) by 120.
\
→ ( 6 )
Write the eqn\\'s (4) & (5) in column form and add the equations to eliminate z - variable.
\
The resultant equation is
→ ( 7 )
To get the eq\\'ns (5) & (6) that contain opposite terms multiply the eq (5) by 7.
\Write the equations in column form and subtract the equations to eliminate z - variable.
\\

The resultant equation is
→ ( 8 )
To get the eq\\'ns (7) & (8) that contain opposite terms multiply the eq (7) by 13 and eq (8) by 14.
\Write the equations in column form and subtract the equations to eliminate x - variable.
\\

The resultant equation is
.
Substitute the value of
in eq (7), and solve for x.
Substitute the values of
and
in eq (4), and solve for z.

.
Therefore, solution of the given system is
.
\
\