The curve is
, and the point is (2, 0).
We can use implicit differentiation to find y \\'.
\The implicit(or total) derivation of
is, \ \

Substitute the values of (x, y ) = (2, 0) in the above equation.
\

.
This is the slope (m ) of the tangent line to the implicit curve at (2, 0).
\To find the tangent line equation, substitute the values of
and (x, y ) = (2,0) in the slope intercept form of an equation.
y = mx + b
\
.
Substitute
and
in y = mx + b.

.
The tangent line equation is
.