The curve is $\"\"$ \ \

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Differentiate on each side with respect to $\"image\"$ . \ \

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$\"\"$ \ \

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Apply product rule in derivatives $\"\"$ \ \

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$\"\"$ \ \

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$\"\"$ \ \

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$\"\"$ is slope of the tangent line. \ \

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The tangent line is parallel to $\"\"$ \ \

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Write the equation $\"\"$ in slope intercept form $\"\"$ , where $\"\"$ is slope and $\"\"$ is $\"\"$ -intercept.

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$\"\"$ \ \

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$\"\"$ \ \

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$\"\"$

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$\"\"$

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$\"\"$ \ \

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$\"\"$ \ \

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Using the $\"\"$ - value find the corresponding $\"\"$ - value with the curve. \ \

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$\"\"$

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$\"\"$

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Therefore tangent point is $\"\"$ \ \

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Find the tangent line equation, substitute the values of $\"\"$ and $\"\"$ in the slope intercept form of an equation $\"\"$ .

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$\"\"$

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$\"\"$

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Substitute $\"\"$ and $\"\"$ in $\"\"$ .

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$\"\"$ \ \

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Solution :

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Tangent line is $\"\"$ .