Step 1 :
\(a)
\The height of the rock after t seconds is
.
Velocity at the surface of the Mars
.
Velocity is derivative of displacement function.
\Differentiate h with respect to t.
\
Velocity of rock after t seconds is
.
Velocity of rock after 2 seconds:
\
Velocity of rock after 2 seconds is 7.56 m/s.
\Step 2 :
\(b)
\The height is 25 m.
\Height of the rock is
.
Since roots of the quadratic function
:
Roots of the quadratic function
:
First root:
\
Second root:
\
Step 3 :
\Velocity at time
.

At height 25 m. the velocity of rock on its way up is
.
Velocity at time
.

At height 25 m. the velocity of rock on its way down is
.
Solution :
\(a) Velocity of rock after 2 seconds is 7.56 m/s.
\(b) The velocity of rock on its way up is
.
The velocity of rock on its way down is
.
\