Step 1:
\(a)
\The function is
.
Find the critical numbers by equating the first derivative to
.

Apply derivative on each side with respect to
.

Equate the derivative to
.

So the function has critical number at
.
Solution :
\The function has critical number at
.
Step 1:
\(b)
\The critical point is
,consider the table summarizes the testing of two intervals determined by the critical number.
| Test interval | \![]() | \
![]() | \
| Test value | \ ![]() | \
![]() | \
sign of ![]() | \
![]() | \
![]() | \
| Conclusion | \Increasing | \ \
Decreasing \ | \
So the function
is increasing on the interval
and decreasing on the interval
.
Solution :
\The function
is increasing on the interval
and decreasing on the interval
.
Step 1:
\(c)
\Use first Derivative Test to identify all relative extrema.
\The derivative of the function is
.
The critical point is
,consider the table summarizes the testing of two intervals determined by the critical number.
| Test interval | \![]() | \
![]() | \
| Test value | \ ![]() | \
![]() | \
sign of ![]() | \
![]() | \
![]() | \
| Conclusion | \Increasing | \ \
Decreasing \ | \
From the fist derivative test the function
changing from positive to negative at
, then
has a relative maximum at
.
Find for
.

So the function
has relative maximum at
.
Solution :
\The function
has relative maximum at
.
Step 1:
\(d)
\Graph the function is
.

Now observe the graph :
\The function has critical number at
.
The function
is increasing on the interval
and decreasing on the interval
.
The function
has relative maximum at
.
Solution :
\The function has critical number at
.
The function
is increasing on the interval
and decreasing on the interval
.
The function
has relative maximum at
.
\
\
\