Step 1 :

 (a)

Thu function and the interval is .

Differentiate with respect to :

Determination of critical points:

The critical points exist when .

Equate to zero:

Solve in the interval .

General solution of is , where is an integer.

.

If , .

If , .

If , .

If , .

The solutions are in the interval .

Solve in the interval .

General solution of is , where is an integer.

.

If , .

If , .

The solutions are in the interval .

The critical points are and the test intervals are .

Interval	Test Value	Sign of	Conclusion
		\ \	Increasing
		\ \	Decreasing
		\ \	Decreasing
		\ \	Increasing
		\ \	Increasing

The function is increasing on the intervals , , and .

The function is decreasing on the intervals and .

Step 1 :

Thu function and the interval is .

The critical points are .

Find the values of at these critical points.

Step 3 :

Find the values of at the end points of the interval.

a

Compare the four values of to find absolute maximum and absolute minimum.

Absolute maximum value is

Absolute minimum value is

Solution:

Absolute maximum value is

Absolute minimum value is