The function is 
Differentiate the function with respect to
.


Differentiate
with respect to
.



Find the inflection point by equating 



Thus the inflection point is
, Split the interval into
, and
| \
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
\
| \
\
\ | \
Down | \
![]() | \
\
| \
\
| \
Up | \
Thus the graph is concave down in the interval
and concave up in the interval
.
step 2:
\Inflection points:
\
Inflection point 
Solution:
\Inflection point 
The graph is concave down in the interval
The graph is concave up in the interval
.