Step 1:
\(a)
\The triangle side is
and angle is 
The laws of sines : 
The angle
is acute angle,
Recall the relation from the ambiguous case :
.
If triangle has one solution and
is an acute angle , then
and 
and 
Substitute
,
in
.


If triangle has one solution, then values of
are
and
.
(b)
\If triangle has two solutions and
is an acute angle , then 
Substitute the corresponding value in above formula
\
Divide each side by 



Finally conclude that 
(c)
\If triangle has no solution and
is an acute angle, then 

Divide each side by 

Substitute
and
in above expression.
.
Solution:
\(a)
\
and 
(b)
\
(c)
\
.