Step 1:
\The equations are
\
The cross product of two normal vectors is the direction vector for the line of intersection.
\The normal vectors of two planes are
\
.
The cross product of two vectors is
\

The direction vector of line of intersection is
.
Step 2:
\Solve the eqn(1) and eqn(2).
\Multiply eqn(1) on each side by 3.
\
.
Subtract
from eqn(2).

Substitute
in eqn(1)

.
There are no solutions for
and
.
So, take the point
as 
.
The
is lie on the line of intersection.
The direction vector of line of intersection is
.
The parametric plane equation is
\


The parametric equation is
.
Solution:
\The parametric equation is
.
(b)
\The equations are
\
.
.
The normal vectors of two planes are
\
.
The angle between two planes is
\
The angle between two planes is
.
Solution:
\The angle between two planes is
.
\
\
\