Step 1 :
\A, B, and C are the points lying on the line
.
Since the point A lies on the y - axis, Substitute
in the line equation.

Thus, the point A is
.
Step 2 :
\The line from
to B is perpendicular to AC .
Means that, the line BD is is perpendicular to AC .
\Find the slope of the line AC .
\The line equation is
.
Write the equation in slope - intercept form of line equation
, where m is slope and b is the y - intercept.
.
Compare the equation with
.
Slope is
.
Since the slopes of the perpendicular lines are negative reciprocals, slope of the line AC is
.
Step 3:
\Find the line BD.
\Point-slope form of line equation is
, where m is the slope and
is the point lies on the line.
Substitute the point
and
in above equation.

Step 4 :
\Point B is the intersection point of the lines AC and BD.
\Substitute
in
.

If
, then
.
Thus, the point B is
.
Step 5 :
\Since AB = BC, point B is the mid point of AC.
\Let the points are
,
, and
.
Mid point
.

Equate the x and y coordinates.
\
Thus, the point C is 
\
\
\