(a)
\Step 1:
\The differential equation is
.
The initial condition is
and
-value is
.
Step size is
.
Euler method is a numerical approach to approximate the particular solution of the differential equation.
\Let
that passes through the point
.
From this starting point, one can proceed in the direction indicated by the slope.
\Use a small step
, move along the tangent line.
and
.
Step 2:
\Use step size
,
,
and
.


So we have
,
,
,
,.....and,


Step 3:
\Proceeding with similar calculations, we get the values in the table:
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From the table particular solution at x = 2 is 3.031.
\Solution:
\The particular solution at x = 2 is 3.031.
\\
\
\
(b)
\Step 1:
\The differential equation is
.
The initial condition is
.
Solution to the differential equation :
\
Integrate on each side.
\
Substitute initial conditions
,
.

The exact solution is
.
Solution:
\The exact solution is
.
\
(c)
\Step 1:
\The differential equation is
.
From Euler method, particular solution at x = 2 is 3.031.
\The exact solution is
.
From the exact solution, the particular solution :
\Substitute x = 2 in exact solution.
\
Solutions to the 3rd degree equation are
.
Imaginary values are neglected.
\So the particular solution at x = 2 is 3.
\Therefore the particular solution is almost same in both methods.
\Solution:
\The particular solution at x = 2 is 3.
\\
\
\
\
\