Step 1:

The functions are $\"\"$ and $\"\"$ .

The vertical lines are $\"\"$ and $\"\"$ .

Graph:

Graph the functions are $\"\"$ and $\"\"$ .

Shade the region bounded by the curves between $\"image\"$ and $\"\"$ .

$\"\"$

Note: The region shaded in blue color is the required area of region.

Step 2:

Definite integral as area of the region:

If $\"image\"$ and $\"image\"$ are continuous and non-negative on the closed interval $\"image\"$ ,

then the area of the region bounded by the graphs of $\"image\"$ and $\"image\"$ and the vertical lines $\"image\"$ and $\"image\"$ is given by

$\"image\"$ .

Observe the graph:

Upper curve is $\"\"$ .

Lower Curve is $\"\"$ .

The vertical lines are $\"\"$ and $\"\"$ .

Area of the region is

$\"\"$

Area of the region is 2.166 sq-units.

Solution:

Graph the region of graph of $\"\"$ and $\"\"$ between $\"image\"$ and $\"\"$ is \ \

$\"\"$

Area of the region is 2.166 sq-units.