Step 1 :
\Freezing point of water
, where
is the change in temperature and ,
is the van t Hoff factor,
is the molality of the solution and
is the molality depression constant =
.
Freezing point :
.
for sodium chloride is 2.

Substitute
and
in above equation.
.

Freezing point of 1 molal aqueous sodium chloride solution is
.
Step 2 :
\Freezing point :
.
for glucose is 3.

Substitute
and
in above equation.
.

Freezing point of 1 molal aqueous glucose solution is
.
Step 3 :
\Observe the above calculations.
\1 molal aqueous sodium chloride has the lower Freezing point compare with 1 molal aqueous glucose.
\Solution:
\1 molal aqueous sodium chloride has the lower Freezing point compare with 1 molal aqueous glucose.