Step 1 :

Tangent line equation is .

At , .

Tangent line equation is .

Differentiate the above equation with respect to .

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The curve equation is .

Considering the function as

Differentiate the curve with respect to .

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Evaluating at . \ \

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The tangent line to the graph at is the line with slope 36 and passing through the point . \ \

Point-slope form of a line equation is .

Let the point is and the slope is .

Substitute the corresponding values in point-slope form.

The tangent line equation is .

Solution:

The tangent line equation is . \ \