Step 1:
\
Find the current through 11
resistor :
Super Position Theorem :
\Take 4V voltage source at a time and replace all other with short or internal resistance.
\
Equivalent resistance :
\11
resistor is in parallel with 7
resistor.

Resistance RT is in series with 5
resistor.

Resistance RP is in parallel with 9
resistor.

Resistance RQ is in series with 3
resistor.

Step 2:
\Circuit current :
\
Current across each resistor :
\
.



Step 3:
\Now Short circuit the second voltage source.
\
Take 8V voltage source at a time and replace all other with short or internal resistance.
\
Equivalent resistance :
\3
resistor is in parallel with 9
resistor.

Resistance RT is in series with 5
resistor.

Resistance RP is in parallel with 11
resistor.

Resistance RQ is in series with 7
resistor.

Step 2:
\Circuit current :
\
Current across each resistor :
\
.



Step 5:
\Current through 11
resistor =
= Current produced by 11
resistor due to 8 V - Current produced by 11
resistor due to 4 V
(Since they are in opposite direction)
\= 0.649 - 0.132
\= 0.517
\Current through 11
resistor is 0.517 A.