Step 1:
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Find the current through 6
resistor :
Super Position Theorem :
\Take one voltage source at a time and replace all other with short or internal resistance.
\.gif\")
Indicate the direction of current in the above circuit.
\Equivalent resistance :
\9
resistor is in parallel with 6
resistor.

Resistance RT is in series with 7
resistor.

Step 2:
\Circuit current :
\
Current across each resistor :
\


Step 3:
\Now Short circuit the second voltage source.
\.gif\")
Indicate the direction of current in the above circuit.
\Equivalent resistance :
\7
resistor is in parallel with 6
resistor.

Resistance RT is in series with 9
resistor.

Step 4:
\Circuit current :
\
Current across each resistor :
\


Step 5:
\Current through 6
resistor =
= Current produced by 6
resistor due to 5 V + Current produced by 6
resistor due to 10 V
= 0.282 + 0.440
\= 0.722
\\