Step 1:
\
Find the current through 8
resistor :
Super Position Theorem :
\Take one voltage source at a time and replace all other with short or internal resistance.
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Indicate the direction of current in the above circuit.
\Equivalent resistance :
\6
resistor is in parallel with 8
resistor.

Resistance RT is in series with 4
resistor.

Step 2:
\Circuit current :
\
Current across each resistor :
\


Step 3:
\Now Short circuit the second voltage source.
\
Indicate the direction of current in the above circuit.
\Equivalent resistance :
\4
resistor is in parallel with 8
resistor.

Resistance RT is in series with 6
resistor.

Step 4:
\Circuit current :
\
Current across each resistor :
\


Step 5:
\Current through Load resistor 8
=
= Current produced by 8
resistor due to 5 V + Current produced by 100
resistor due to 7V
=0.2884+0.2692
\= 0.5576
\Current through 8
resistor is 0.5576 A.
Solution:
\Current through 8
resistor is 0.5576 A.