Step 1:
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Step 2:
\Find the current through the resistance R4.
\Thevenins Theorem :
\Thevenins Theorem states that it is possible to simplify any linear circuit, no matter how complex, to an equivalent circuit with just a single voltage source and series resistance connected to a load.
\Now reduce the circuit to a equivalent Thevenins circuit .
\Find the Equivalent Resistance (Rs):
\Find the Thevenin resistance by removing all power sources in the original circuit (voltage sources shorted and current sources open) and calculating total resistance between the open connection points.
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6Ω Resistor in parallel with the 20Ω Resistor .
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Now the resistance
in series with 5Ω Resistor .
So thevenins resistance
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Find the Equivalent Voltage (Vs):
\Find the Thevenin source voltage by removing the load resistor from the original circuit and calculating voltage across the open connection points where the load resistor used to be.
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Apply KVL to the above circuit .
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(The current in the second loop is zero since it is kept open )

So the voltage drop across the 20 Ω resistor can be calculated as:
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Therefore the Thevenins Equivalent circuit is shown below with the 15 Ω resistor connected.
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The current across the load is
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