step 1:

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(b) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find $\"\"$ -coordinate value at $\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

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Find the slope of the $\"\"$ .

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Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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step 2:

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(c) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

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Find the slope of the $\"\"$ .

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Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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step 3:

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(d) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

\

Find the slope of the $\"\"$ .

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Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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step 4:

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(e) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

\

Find the slope of the $\"\"$ .

\

Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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step 5:

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(e) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

\

Find the slope of the $\"\"$ .

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Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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step 6:

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(e) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

\

Find the slope of the $\"\"$ :

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Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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step 7:

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(e) The function is $\"\"$ .

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At the point $\"\"$ , $\"\"$ .

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Find corresponding $\"\"$ -coordinate value at $\"\"$ .

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$\"\"$ .

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substitute $\"\"$ in $\"\"$ .

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$\"\"$

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The point $\"\"$ is $\"\"$ .

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Find the slope of the $\"\"$ :

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Slope of the two points $\"\"$ and $\"\"$ is $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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Slope of the secant line $\"\"$ is $\"\"$ .

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Step 1:

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Slope of the tangent is derivative of the function.

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The function is $\"\"$ .

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Differentiate on each side with respect to $\"\"$ .

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$\"\"$

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Slope of the tangent line at $\"\"$ .

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$\"\"$

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Slope of the tangent line is $\"\"$ .

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we have the point $\"\"$ as $\"\"$ .

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Point-slope form of line equation $\"\"$ .

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Substitute slope $\"\"$ and the point $\"\"$ in the above formula.

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$\"\"$

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The equation of a tangent line $\"\"$ .

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\