Step 1:

25.00  mL of 0.100 M HCL is 2.5 mMOL of .

The chemical reaction of Methylamine reacts with water :

(a)

When 10.00 mL of is added.

25.00  mL of 0.100 M HCL is 2.5 mMOL of .

10.00  mL of 0.100 M is 1 mMOL of .

Number of moles of acid left after reaction :

2.5 mMOL of -  1 mMOL of = 1.5 mMOL of

Find .

Step 2:

(b)

When 25.00 mL of is added.

25.00  mL of 0.100 M HCL is 2.5 mMOL of .

25.00  mL of 0.100 M is 2.5 mMOL of .

Number of moles of acid left after reaction :

2.5 mMOL of -  2.5 mMOL of = 0 mMOL of

At equilibrium concentration :

The HCL solution of ionization constant is

Find .

Step 3:

(c)

When 25.00 mL of is added.

25.00  mL of 0.100 M HCL is 2.5 mMOL of .

35.00  mL of 0.100 M is 3.5 mMOL of .

Number of moles of base left after reaction :

3.5 mMOL of - 2.5 mMOL of -  = 1 mMOL of

Find .

Solution :

(a) .

(b) .

(c) .