Step 1:

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(a) \ \

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Concentration of silver chloride is [AgCl] = 10.0 M.

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The solubility product of the two reactions are as follows. \ \

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$\"\"$ Solubility product $\"\"$ .

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$\"\"$ Solubility product: $\"\"$ .

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$\"\"$ Solubility product: $\"\"$ .

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So the overall concentration of silver [Ag] is sum of the concentration of the silver used in the three reactions.

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$\"\"$

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The overall reaction is $\"\"$ .

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Solubility product of silver cholride in the overall reaction is $\"\"$ .

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$\"\"$

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Solubility product is $\"\"$ .

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Step 2:

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Let x be the concentration $\"\"$ and $\"\"$ .

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Then the concentration of the $\"\"$ is 10-2x. \ \

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Solubility product $\"\"$

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$\"\"$

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The solubility of the silver chloride in 10.0 M ammonia is 0.475 M.

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Solution :

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The solubility of the silver chloride in 10.0 M ammonia is 0.475 M.

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Step 1:

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(b)

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Concentration of silver chloride is [AgCl] = 10.0 M.

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The overall reaction is $\"\"$ .

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Let x be the concentration $\"\"$ and $\"\"$ .

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Then the concentration of the $\"\"$ is 10-2x.

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The solubility of the silver chloride in 10.0 M ammonia x is 0.475 M.

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Concentration of the $\"\"$ is $\"\"$ .

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Concentration of the $\"\"$ is 9.05 M.

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Solution :

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Concentration of the $\"\"$ is 9.05 M.