(5)
\Step 1:
\The function is
and point is
.
Apply derivative on each side with respect to x.
\
The derivative of the function represents the slope of the tangent line.
\Find the slope of the tangent line at a point
.
Substitute
in
.

Therefore the slope of the tangent line is
.
Step 2:
\Find the tangent line equation at a point
.
Point - slope form of a line equation :
.
Substitute
and
in point - slope form.

Therefore the tangent line equation is
.
Solution :
\Therefore the tangent line equation is
.
(6)
\Step 1:
\The function is
and point is
.
Differentiate
on each side with respect to
.

Find the critical points.
\The critical points exist when
.
Equate
to zero.

The critical point is
.
Step 2:
\Rewrite the function.
\
The test intervals are
and
.
| Interval | \![]() | \
![]() | \
| Test Value | \ | \
![]() | \
Value of ![]() | \
![]() | \
![]() | \
Sign of ![]() | \
![]() | \
![]() | \
| Conclusion | \Decreasing | \Increasing | \
The function is increasing on the interval
.
The function is decreasing on the interval
.
The point is
.
The point
lies on the interval
.
Therefore the function
is increasing at the point
.
Solution :
\The function
is increasing at the point
.