(11)
\Step 1:
\The function is
and interval is
.
Absolute maxima or minima are exist either at the end points or at the critical numbers.
\Find the critical numbers :
\
is differentiable at all points because its a polynomial.
Therefore the solutions of
are the only critical numbers.
Differentiate
on each side with respect to t.

Equate
to zero.

and
and 
and
and 
The critical number are
,
and
.
The end points are
and
.
Step 2:
\Find the value of f at the critical numbers.
\Substitute
in
.

.
Substitute
in
.

.
Substitute
in
.

.
Step 3:
\Find the value of f at the end points of the interval.
\Substitute
in
.
\

.
Substitute
in
.
\

.
Since the largest value is
, absolute maximum is
.
Since the smallest value is
, absolute minimum is
.
Solution :
\Absolute maximum is
.
Absolute minimum is
.
\
(12)
\Step 1:
\The function is
and interval is
.
Absolute maxima or minima are exist either at the end points or at the critical numbers.
\Find the critical numbers :
\
is differentiable at all points because its a polynomial.
Therefore the solutions of
are the only critical numbers.
Differentiate
on each side with respect to x.

Equate
to zero.

The critical number are
.
The end points are
and
.
Step 2:
\Find the value of h at the critical numbers.
\Substitute
in
.

.
Find the value of h at the end points of the interval.
\Substitute
in
.
\

\
.
Substitute
in
.
\

.
Since the largest value is
, absolute maximum is
.
Since the smallest value is
, absolute minimum is
.
Solution :
\Absolute maximum is
.
Absolute minimum is
.