(10)
\Step 1:
\Perimeter of the three pens is
ft
Let each pen has length
ft and breadth
ft.
Since there are three pens total length is
.
Total width is
.
ft.


. \ \
Area of the total fencing is
.
Substitute
.


.
The area of the rectangular field is always positive.
\

and
.
and
.
is positive on the interval
.
Step 2:
\Find the dimensions of the rectangular field, that will enclose the maximum area.
\
Apply derivative on each side with respect to
.



Find the critical numbers by equating
.


ft.
Substitute
in
.


ft.
Step 3:
\The maximum value of
occurs at either at critical number or at end point of the interval
.
Substitute
in
.
.
Substitute
in
.



.
Substitute
in
.




sq ft. \ \
The maximum area of a rectangular fencing is
sq ft. \ \
The dimensions of the rectangular field are
ft and
ft. \ \
Solution:
\The dimensions of the rectangular field are
ft and
ft.
The maximum area of a rectangular fencing is
sq ft.