A box slides at a constant rate of 4.0 m/s down an incline that makes a 40º angle with the horizontal. 3) What is the coefficient of kinetic friction?

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Step 1:

The velocity of the box on the inclined plane is 4.0 m/s.

The inclination angle is 40º.

The component of the gravity force down the incline is equal to the frictional force.

The formula for the Kinetic friction is $\"\"$ .

The component of the gravity force is $\"\"$ .

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Therefore the coeffiecient of friction is 0.839.

Where $\"\"$ is coefficient of kinetic friction,

m is the mass,

g is the acceleration due to gravity (9.8 m/s²),

$\"\"$ is the inclination angle.

The kinetic friction force is $\"\"$ .

Where v is velocity.

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Find the coefficient of kinetic friction.

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