Step 1:

The curve equation is and a line equation .

Sketch the graphs :

Shade the region above the curve and region below the line .

Now find the intersection of the curve and a line.

Find the intersection points from the graph and .

Definite integral as area of the region:

If and are continuous and non-negative on the closed interval ,

then the area of the region bounded by the graphs of and and the vertical lines and is given by

.

Apply power rule of integration: .

Therefore area above the curve and region below the line is 36 sq units.

Step 1:

The curve equation is and a line equation .

Sketch the graphs :

Shade the left side  region of the curve and right side region of the line .

Now find the intersection of the curve and a line.

Find the intersection points from the graph and .

Definite integral as area of the region:

If and are continuous and non-negative on the closed interval ,

then the area of the region bounded by the graphs of and and the vertical lines and is given by

.

Apply power rule of integration: .

Therefore area above the curve and region below the line is 24.67 sq units.