Step 1:
\The series is
.
The Comparison Test :
\Suppose that
and
are series with positive terms.
(i) If
is convergent and
for all n , then
is also convergent.
(ii) If
is divergent and
for all n, then
is also divergent.
\
The dominant part of the numerator is 1 and the dominant part of the denominator is
.
Now compare the given series with the series
.
Observe that
.
Step 2 :
\The obtained series is
.
Definition of p - series :
\The p - series
is convergent if
and divergent if
.
Here p = 1.
\Hence the series
is divergent.
Here
and
is divegent.
By comparison test,
also diverges.
Step 3:
\\
Solution :
\
is divergent.
\
\
\
\
\
\
Step 1:
\The series is
.
The Comparison Test :
\Suppose that
and
are series with positive terms.
(i) If
is convergent and
for all n , then
is also convergent.
(ii) If
is divergent and
for all n, then
is also divergent.
\
The dominant part of the numerator is 1 and the dominant part of the denominator is
.
Now compare the given series with the series
.
Observe that
.
Step 2 :
\The obtained series is
.
Definition of p - series :
\The p - series
is convergent if
and divergent if
.
Here p = 1.
\Hence the series
is divergent.
Here
and
is divegent.
By comparison test,
also diverges.
Solution :
\
is divergent.
\
\
\
\
Step 1:
\\
The series is
.
Integral test :
\Suppose
is continuous , positive and decreasing on the interval
then
(i)
is convergent the
is also convergent.
(i)
is divergent the
is also divergent.
The function
is continuous , positive and decreasing on the interval
.



The series is divergent.
\Solution:
\The series is divergent.