\
Step 1:
\Claim : The Car accidents are equally distributed for each of the 12 months.
\Hypothesis test for the claim :
\One of these statements must become the null hypothesis , and the other should be the alternate hypothesis.
\The car accidents are equally distributed, hence the proportion of car accident for each month is
.
Null hypothesis : \ \
\The null hypothesis contains equality.
\So for the above, the null hypothesis H0 : p = 0.5. \ \
\Alternate hypothesis :
\The statement that does not contain equality is the alternative hypothesis.
\So for the above scenario, the alternate hypothesis Ha :
.
Step 2:
\Find Chi square statics.
\Chi square statics are calculated by the formula :
.
It is expected that number of car accidents are equally likely for 12 months.
\Total Observed frequency is 512.
\Therefore expected frequency is
.
| Month | \Car Accidents (Observed Frequency) | \Car Accidents (Expected Frequency) | \Chi Square statistics | \
| January | \38 | \43 | \0.5814 | \
| February | \30 | \43 | \3.9302 | \
| March | \46 | \43 | \0.2093 | \
| April | \40 | \43 | \0.2093 | \
| May | \46 | \43 | \0.2093 | \
| June | \49 | \43 | \0.83721 | \
| July | \47 | \43 | \0.3721 | \
| August | \50 | \43 | \1.1395 | \
| Sepetember | \50 | \43 | \1.1395 | \
| October | \42 | \43 | \0.02326 | \
| November | \37 | \43 | \0.83721 | \
| December | \37 | \43 | \0.83721 | \
| Total | \512 | \516 | \10.3255 | \
Chi square statics :
.
Step 3:
\Step 4:
\Find the critical values.
\Significance value is 0.05.
\
.
The sample size is 12.
\Degree of freedom
.
Calculate the critical values using calculator.
\Follow these steps to evaluate critical values.
\1.Select invT()
\[2nd --> VARS --> 4 ]
\2.Enter the values of
and df.
area : 0.05
\df : 11
\3.Now press Enter in calculator to view answer.
\invT(0.05, 12)
\=-1.79588
\Critical value is -1.79588.
\Step 5:
\Reject H0 if
.
Chi square statics :
.
Critical value is -1.79588.
\
.
Reject H0 as
.
Conclusion :
\There is insufficient evidence to warrant rejection of the claim that the car accidents are equally distributed for each of the 12 months.
\Step 6:
\A Elizabethtown firefighter said that accidents occur more often in the summer.
\Since the claim is reject, there is a possiblity of the claim that accidents occur more often in the summer.
\Hence the claim that accidents occur more often in the summer is valid.