Step 1:

Initially at , the switch is open.

The resistance and the resistance are in series.

Find the current in the circuit.

Substitute , and in the above formula.

Initially current flowing in the circuit is .

Step 2:

After , the switch is closed.

The resistor is short circuited.

The resistance and the inductor are in series.

The voltage across each component is equal to the total circuit voltage.

Substitute and in the above.

This is first order linear differential equation.

Solution of first order linear differential equation is , where .

Solution of the differential equation : .

Substitute corresponding values.

Initial at the value of current is .

Therefore substitute in equation (1).

Therefore current flowing in the circuit is .

Solution :

Current flowing in the circuit is .

Step 1:

Find the voltage across inductor .

Volatge across inductor is .

Substitute and in .

Solution :

Volatge across inductor is .