Step 1:

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Observe the circuit.

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The resistors $\"\"$ , $\"\"$ and $\"\"$ looks like $\"\"$ network.

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For convenience change into equivalent $\"\"$ network which makes us to find the total resistance of the circuit.

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From the circuit $\"\"$ .

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Redraw the circuit.

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$\"\"$

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Formula for the resistors when the $\"\"$ network is changed into $\"\"$ network.

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$\"\"$

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$\"\"$

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$\"\"$

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Here

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$\"\"$ , $\"\"$ and $\"\"$ .

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From the above formulae,

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$\"\"$

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$\"\"$ .

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$\"\"$

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$\"\"$ .

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$\"\"$

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$\"\"$ .

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$\"\"$ comes parallel with $\"\"$ .

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Therefore, resultant resistance is $\"\"$ .

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$\"\"$

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$\"\"$ .

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Above resultant comes in series with $\"\"$ .

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Therefore resultant is $\"\"$ .

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$\"\"$

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Then the circuit becomes

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$\"\"$

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Observe the circuit, $\"\"$ comes in parallel with $\"\"$ .

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Thus resultant resistance willbe

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$\"\"$

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Above resistance is in parallel with $\"\"$ .

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Thus resultant resistance willbe

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$\"\"$

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Total resistance of the circuit between $\"\"$ and $\"\"$ is $\"\"$ .

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Solution :

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Total resistance of the circuit between $\"\"$ and $\"\"$ is $\"\"$ .