(1)
\Step 1:
\Observe the circuit.
\The resistors
and
are in parallel.
The equivalent resistance is
.
Substitute
and
.

.
The resistors
and
are in parallel.
The equivalent resistance is
.
Substitute
and
.

.
Step 2:
\Redraw the circuit replacing the resistors by
and
.

The current passing through the resistor
is
.
Since
and
are in series, the current flowing the resistor
is same.
Equivalent series resistamce is
.

Equivalent series resistamce is
.
Voltage applied to the circuit, voltage across
and
are equal, since they are connected in parallel.
.
Voltage drop across
is
.

Therefore, voltage applied to the circuit is 40 V.
\Solution :
\Voltage applied to the circuit is 40 V.
\\
\
\
(2)
\Step 1:
\Find the current
passing through the resistor
.
Observe the equivalent circuit.
\Find the voltage drop across the resistor
.
Voltage drop across aross
is
.

Voltage drop across aross
is
.
is the parallel combination of
and
.
Since
and
are in parallel, the current flowing through
is
.
.
Therefore current passing through the resistor
is
.
Step 2:
\Find the current
passing through the resistor
.
The current flowing through
is
.
.
Therefore current passing through the resistor
is
.
Solution:
\Current passing through the resistor
is
.
Current passing through the resistor
is
.
\
(3)
\Step 1:
\Find the current
passing through the resistor
.
Find the voltage drop across the resistor
is
.
is the parallel combination of
and
.
Since
and
are in parallel, the current flowing through
is
.
.
Therefore current passing through the resistor
is
.
Step 2:
\The current flowing through
is
.
.
Therefore current passing through the resistor
is
.
Solution:
\Current passing through the resistor
is
.
Current passing through the resistor
is
.