\
(1)
\\
(1)
\Step 1:
\Redraw the circuit showing branch currents.
\
Apply KVL for the first loop.
\
Apply KVL for the second loop.
\
Substitute
in equation (1).

Since the current is in opposite direction to the assumed current direction,
.
Solution:
\The branch current is
.
\
\
(2)
\Step 1:
\Observe the circuit.
\Apply KVL for the first loop.
\
The branch current is
. (from (1))


The branch current is
.
Solution:
\The branch current is
.
\
(3)
\Step 1:
\Observe the circuit.
\The branch currents are
and
.
The current flowing through the resistor
is
.

The branch current is
.
Solution :
\The branch current is
.