Step 1 :

The function is .

is continuous on closed interval  then there exists a number  in the closed interval such that .

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Apply integration on the left side of the function.

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Use the fundemental therom :

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Step 2 :

Find the value of c :

The value of exists between , therefore  is not to be considered.

The value exists between , therefore the value of is .

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The

the x-coordinates of the point

Solution :

The value of is .