Step 1:

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The mass of the Chris is $\"\"$ . \ \

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Chris falls for $\"\"$ before the bungee cord begins to stretch. \ \

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The cord obeys Hookes law, $\"\"$ . \ \

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The force is $\"\"$ .

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$\"\"$

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The potential energy of the person is $\"\"$ . \ \

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The potential energy of the person after the bungee cord begins to stretch is $\"\"$ .

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Total potential energy below the bridge is $\"\"$ .

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$\"\"$ \ \

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$ .

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The Chris foot below the bridge before coming to a stop is $\"\"$ .

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The Chris foot below the bridge before coming to a stop is $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$ .

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Substitute $\"\"$ , $\"\"$ and $\"\"$ . \ \

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$\"\"$

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$\"\"$ .

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The Chris foot below the bridge before coming to a stop is $\"\"$ .

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The Chris foot below the bridge before coming to a stop is $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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The solutions of $\"\"$ . \ \

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Recognize that all the kinetic energy gets converted to spring energy, and the jumper comes to a a stop. \ \

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Use the energy balance equation is \ \

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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We know that mg times his change in height (Potential Energy lost) while the cord is stretching is equal to ½kx²

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