Step 1:

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The curve equations are $\"\"$ and $\"\"$ .

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Graph the functions $\"\"$ and $\"\"$ .

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Shade the required region.

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$\"\"$

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Observe the graph :

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Region enclosed by the given curves is between $\"\"$ and $\"\"$ .

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Step 2:

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Area between the curves $\"\"$ and $\"\"$ and between $\"\"$ and $\"\"$ is

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$\"\"$ .

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Here $\"\"$ and $\"\"$ .

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Area of the region , $\"\"$ .

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Integral of symmetric function:

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If $\"\"$ is even function, then $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$

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Area of the region is $\"\"$ sq-units.

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Solution;

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Area of the region is $\"\"$ sq-units.

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Step 1:

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The curve equations are $\"\"$ , $\"\"$ and the lines $\"\"$ to $\"\"$ .

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Graph the functions $\"\"$ , $\"\"$ , $\"\"$ and $\"\"$ .

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Shade the required region.

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$\"\"$

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Observe the graph :

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Region enclosed by the given curves is between $\"\"$ and $\"\"$ .

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Step 2:

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Area between the curves $\"\"$ and $\"\"$ and between $\"\"$ and $\"\"$ is

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$\"\"$ .

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Observe the graph:

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In the interval $\"\"$ ,

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Upper curve is $\"\"$ and the lower curve is $\"\"$ .

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In the interval $\"\"$ ,

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Upper curve is $\"\"$ and the lower curve is $\"\"$ .

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In the interval $\"\"$ ,

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Upper curve is $\"\"$ and the lower curve is $\"\"$ .

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Area of the region, $\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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Area of the region is $\"\"$ sq-units.

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Solution:

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Area of the region is $\"\"$ sq-units.