A 1.8-kg grindstone in the shape of a uniform cylinder of radius 0.20 m acquires a rotational rate of 22 rev/s from rest over a 6.0-s interval at constant angular acceleration.

Calculate the torque delivered by the motor.

Mass of grindstone is $\"\"$ kg.

Uniform cylinder radius is $\"\"$ .

Grindstone rotational rate is 22 rev/s in a time of 6 s.

Find the torque.

Torque $\"\"$ , where I is the moment of inertia and $\"\"$ is the acceleration.

Angular velocity is $\"\"$ rad/s.

Angular acceleration is $\"\"$ rad/s².

$\"\"$

Moment of inertia of cylinder is $\"\"$ .

$\"\"$

$\"\"$ .

Substitute $\"\"$ and $\"\"$ in $\"\"$ .

$\"\"$

Torque required to produce the acceleration 0.83 Nm.