If the coefficient of static friction between a car\\'s tires and the pavement is 0.65, calculate the minimum torque that must be applied to the 66-cm-diameter tire of a 1080-kg automobile in order to "lay rubber" (make the wheels spin, slipping as the car accelerates). Assume each wheel supports an equal share of the weight.

Co-efficient of static friction between a car\\'s tires and the pavement is 0.65.

Diameter of the tire is 66 cm.

Radius of the tire is .

Mass of the automobile is 1080 kg.

Force acting on the wheels is .

Assume each wheel supports an equal share of the weight then

Force acting on each wheel is 2646 N.

Maximum static force of friction is .

Torque:

Since the road is tangent to the tire, .

minimum torque applied is 567.567 N-m.