(1)
\Step 1:
\Find the Thevinins equivalent impedance.
\1.Open the load resistor.
\2.Open Current Sources and Short Voltage Sources.
\3.Calculate the Open Circuit Resistance. This is the Thevenin impedance (ZTH).
\Redraw the circuit :
\
Step 2:
\Observe the circuit:
\
is in series with
.


in polar form can be written as
.
Solution:
\
\
\
(2)
\Step 1:
\Find the thevinins equivalent voltage.
\1.Open the load resistor.
\2.Calculate the Open Circuit Voltage. This is the Thevenin Voltage (VTH).
\Use Superposition principle to calculate volatge across A and B.
\Find the current through
.
Super Position Theorem :
\Take one voltage source at a time and replace all other with short or internal resistance.
\
in complex form can be written as
.
Current in the circuit is
.
Current in the circuit is 
Voltage drop acoss
:
.


Step 2:
\Take one voltage source at a time and replace all other with short or internal resistance.
\
in complex form can be written as
.
Current in the circuit is
.

Current in the circuit is 
Voltage drop acoss
:
.



Step 3:
\By superposition principle :
\The Voltage acoss the terminal A and B is
.


Thevinins equivalent voltage is 
Solution:
\