\
\
Step 1:
\Use Superposition principle to calculate volatge across A and B.
\Super Position Theorem :
\Take one current source at a time and replace all other with voltage with short or internal resistance and current sources with open.
\
The current flowing in the circuit is
.
in polar form can be written as
.

in complex form can be written as
.
Apply current divider rule:
.
Find the total impdenace
.
is in series with
.


is in series with
.


is in parallel to 

is in series with
,
and 


Current divider rule:
\ 

Find the voltage drop across the impedance
.


\
V.
Step 2:
\Take one voltage source at a time and eplace all other with voltage with short or internal resistance and current sources with open.
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The voltage in the circuit is 
in polar form can be written as
.

in complex form can be written as
.
\
Apply KVL to loop 1:
\
Find the voltage drop across the impedance
.


\
V.
Step 3:
\By superposition principle :
\The Voltage acoss the resistor
is
.




Voltage acoss the resistor
is 
Solution:
\Voltage acoss the resistor
is 