An electric dipole is formed from ±1.00nC charges spaced 4.00 mm apart.

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The dipole is at the origin, oriented along the x-axis. What is the electric field strength at the point

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( x, y ) = ( 14.0 cmcm , 0 cm )

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Express your answer with the appropriate units.

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( x, y ) = ( 0 cm, 14.0)

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cm

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Express your answer with the appropriate units.

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Step 1: $\"\"$ $\"\"$

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The dipole is at the origin and oriented along the $\"\"$ -axis, and so the point $\"\"$ along the axis of dipole.

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The electric field is $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$ .

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The electric field strength at $\"\"$ is $\"\"$ .

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Step 2:

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The dipole is at the origin and oriented along the $\"\"$ -axis, and so the point $\"\"$ is perpendicular to to the dipole.

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The electric field is $\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$ . $\"\"$

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The electric field strength at $\"\"$ is $\"\"$ .

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Solution:

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The electric field strength at $\"\"$ is $\"\"$ .

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The electric field strength at $\"\"$ is $\"\"$ .

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along the axis of dipole.

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$\"\"$