\
Step 1:
\Draw the related diagram:
\
The angle of the field at the dot from the upper left charge
is
.
The angle of the field at the dot from the lower left charge
is
.
The angle of the field at the dot from the lower right charge
is
.
Electric field due to charged particle is
, where
.
is the permittivity of free space
.
is the charge of the electron.
is the distance between the two point charges.
Step 2:
\The distance between the upper left charge and the point
is
.
For the charged particle along upper left surface is
.
The distance between the lower left charge and the point
is
.
For the charged particle along lower left surface is
.
The distance between the lower right charge and the point
is
.
For the charged particle along lower right surface is
.
Step 3:
\Find the net electric field.
\
is sum of horizontal and vertical components.
Find the sum of horizontal components.
\
.
Substitute
and
.


.
The horizontal component is
.
Find the sum of vertical components.
\
.
Substitute
and
.


.
The vertical component is
.
.
.
The electric field at point
in component form is
.
Therefore
.
Find the magnitude of electric field strength.
\
Strength of the electric field is 
Find the direction of electric field.
\

Direction of electric field is
above the
-axis.
Solution:
\Strength of the electric field is 
Direction of electric field is
above the
-axis.
\
\