The function is $\"\"$

To find the slope of tangent line, derivative with respect to x to the above function.

$\"\"$

Substitute x = 0 in the above equation.

$\"\"$

To find the y-coordinate of the point, substitute x = 0 in the original function.

$\"\"$

The point-slope from of line equation is $\"\"$ , where m = slope and $\"\"$ is point.

Substitute $\"\"$ in the point-slope form of line equation.

$\"\"$

The tangent line equation is $\"\"$ .

Graph :