$\"\"$

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The investment P = $750 and annual rate $\"\"$ .

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The annual rate $\"\"$ .

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Formula for continuous compounding : $\"\"$ .

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Substitute P = $750 and r = 0.105.

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$\"\"$

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Time required for the balance to double.

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Substitute A(2P) = $1500.

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$\"\"$ \ \

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$\"\"$

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$\"\"$ \ \

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Apply inverse property: $\"\"$ .

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$\"\"$

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$\"\"$ \ \

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$\"\"$

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Time required for the balance to double is 6.6 yrs. $\"\"$

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The formula for n compounding per year : $\"\"$ .

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n = one year = 12 months.

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Consider $\"\"$ .

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Substitute P = $750, t = 10 years, n = 12, and r = 0.105 in above equation.

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$ .

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After 10 years, the amount is $2133.5.

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$\"\"$

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Time required for the balance to double is 6.6 yrs. \ \

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After 10 years, the amount is $2133.5.