Solve the equations algebraically.
\
From equation (1):
\
From equation (2):
\
Equate the the left hand side of equations (3) and (4).
\


Apply zero product property.
\
and
and
.
Substitute the
values in equation (1).
For
,




.
For
,






.
Thus, the intersection points are
and
.
Consider
.
Compare it to general form
.
Discriminant
Since
, the equation represents a hyperbola.
Consider
.
Compare it to general form
.

Since
and
have different signs and equal coefficients,
the equation represents a circle.
\Graph the equations:
\
Observe the graph:
\The intersection points are
and
.
The intersection points are
and
.