The equation is
.
The solution is cube root of negative one.
\To find nth root of complex numbers, the complex number has trigonometric form.
\So the complex number change into trigonometric form.
\The complex number is
.
The trigonometric form of complex number
is
.
The absolute value (modulus) of
is
.
The absolute value (modulus) of
is
.
The reference angle
is given by
.
The value of
and the complex number
lies in quadrant II (
).
So, the angle is
.
The trigonometric form of complex number
is 
The solution is cube root of
.
The nth root of complex number formula is
.
(Write solution in trigonometric form)
(Apply nth root formula)
(Substitute
)
(Simplify)
So for
, the cube roots are as follows:
(Write trigonometric form of complex number)
(Substitute
)
(Simplify)
(Write trigonometric form of complex number)
(Substitute
)
(Simplify)
(Write trigonometric form of complex number)
(Substitute
)
(Simplify)
The solutions are
.