(a)
\The equation is
and the point is
.
To tell the ordered pair
is a solution, substitute the values of
in the original equation.


.
The above statement is true.So the point
is a solution of the equation
, and \ \
The point
is lies on the graph of
.
(b)
\The equation is
and the point is
.
To check the solution, substitute the values of
in the original equation.



.
The above statement is false.So the point
is not a solution of the equation
, and \ \
The point
does not lies on the graph of
.
(a) The point
is lies on the graph of
.
(b) The point
does not lies on the graph of
.