(a)
\The equation is
and the point is
.
To check the solution, substitute the values of
in the original equation.



.
Since the above statement is true, the point
is a solution of the equatio
, and
The point
lies on the graph of
.
(b)
\The equation is
and the point is
.
To check the solution, substitute the value of
in the original equation.



.
Since the above statement is false, the point
is not a solution of the equation
, and
The point
does not lies on the graph of
.
(a) The point
lies on the graph of
.
(b) The point
does not lies on the graph of
.