\
The equation for cross-section is
.
(a)
\Find the intercepts.
\Find the
-intercept by substituting
in the equation.




-intercept is
.
Find the
-intercept by substituting
in the equation
.





Since the solutions are imaginary, there is no
-intercept.
Intercept is
.
\
(b)
\Test algebraically symmetric with respect to the
-axis:
Substitute
for
in
.


Because
is equivalent to
, the graph is symmetric with respect to the
-axis.
\
Test algebraically symmetric with respect to the
-axis:
Substitute
for
in
.


Because
is not equivalent to
, the graph is not symmetric with respect to the
-axis.
\
\
Test algebraically symmetric with respect to the origin:
\Substitute
for
and
for
in
.


Because
is not equivalent to
, the graph is not symmetric with respect to the origin.
(a) Intercept is
.
(b)
-axis symmetry.