The functions are  and .

(a)

Solve .

Apply logarithm one to one property : if ,then .

.

The point is on the graph of is .

(b)

Solve .

Apply logarithm one to one property : if ,then .

The point is on the graph of is .

(c)

Solve for .

Find the intersection point.

Equate and .

Apply logarithm one to one property : if ,then .

Hence there is no real solution.

The graphs of the functions and are does not intersect.

(d)

Solve for .

.

Substitute and in the above equation.

Apply logarithm product property : .

Apply logarithm one to one property : if ,then .

Solve for by factorizing the quadratic equation.

Apply zero product rule.

or

or

Since does not exist,hence it is not considered.

Therefore, the solution is .

The solution set is .

(e)

Solve for .

Substitute and .

Apply logarithm quotient property : .

Apply logarithm one to one property : if ,then .

Solve for .

Therefore,the solution is .

The solution set is .

(a) The solution set is and the point is on the graph of is .

(b) The solution set is and the point is on the graph of is .

(c) The grpahs of the functions and are does not intersect.

(d)The solution set is .

(e)The solution set is .